Word Break Count

You are given a non-empty string s and a dictionary of words. Your task is to count the number of ways to partition the string s such that every substring in the partition is a valid word in the dictionary.

We can solve this problem using dynamic programming. Let \(dp[i]\) represent the number of ways to partition the substring s[0:i]. The recurrence is given by:

\(dp[i] = \sum_{j=0}^{i-1} dp[j]\) if \(s[j:i] \in \text{wordDict}\), with the base case \(dp[0] = 1\).

Output the final result \(dp[n]\) where \(n\) is the length of s.

inputFormat

The input is read from stdin and has the following format:

• The first line contains the string s.
• The second line contains an integer n, representing the number of words in the dictionary.
• The following n lines each contain one word from the dictionary.

outputFormat

Print a single integer to stdout that represents the number of ways to partition the string s using words from the dictionary.

catsanddog
5
cat
cats
and
sand
dog

2