#D8056. Phoenix and Balance

    ID: 6696 Type: Default 2000ms 256MiB

Phoenix and Balance

Phoenix and Balance

Phoenix has n coins with weights 2^1, 2^2, ..., 2^n. He knows that n is even.

He wants to split the coins into two piles such that each pile has exactly n/2 coins and the difference of weights between the two piles is minimized. Formally, let a denote the sum of weights in the first pile, and b denote the sum of weights in the second pile. Help Phoenix minimize |a-b|, the absolute value of a-b.

Input

The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases.

The first line of each test case contains an integer n (2 ≤ n ≤ 30; n is even) — the number of coins that Phoenix has.

Output

For each test case, output one integer — the minimum possible difference of weights between the two piles.

Example

Input

2 2 4

Output

2 6

Note

In the first test case, Phoenix has two coins with weights 2 and 4. No matter how he divides the coins, the difference will be 4-2=2.

In the second test case, Phoenix has four coins of weight 2, 4, 8, and 16. It is optimal for Phoenix to place coins with weights 2 and 16 in one pile, and coins with weights 4 and 8 in another pile. The difference is (2+16)-(4+8)=6.

inputFormat

Input

The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases.

The first line of each test case contains an integer n (2 ≤ n ≤ 30; n is even) — the number of coins that Phoenix has.

outputFormat

Output

For each test case, output one integer — the minimum possible difference of weights between the two piles.

Example

Input

2 2 4

Output

2 6

Note

In the first test case, Phoenix has two coins with weights 2 and 4. No matter how he divides the coins, the difference will be 4-2=2.

In the second test case, Phoenix has four coins of weight 2, 4, 8, and 16. It is optimal for Phoenix to place coins with weights 2 and 16 in one pile, and coins with weights 4 and 8 in another pile. The difference is (2+16)-(4+8)=6.

样例

2
2
4
2

6

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