#D506. Hate "A"
Hate "A"
Hate "A"
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 ≤ |t| ≤ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
inputFormat
Input
The first line of input contains a string t (1 ≤ |t| ≤ 10^5) consisting of lowercase English letters.
outputFormat
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
样例
ababacacbbcc
ababacac