#D3775. Recursive Queries
Recursive Queries
Recursive Queries
You are given a permutation p_1, p_2, ..., p_n. You should answer q queries. Each query is a pair (l_i, r_i), and you should calculate f(l_i, r_i).
Let's denote m_{l, r} as the position of the maximum in subsegment p_l, p_{l+1}, ..., p_r.
Then f(l, r) = (r - l + 1) + f(l, m_{l,r} - 1) + f(m_{l,r} + 1, r) if l ≤ r or 0 otherwise.
Input
The first line contains two integers n and q (1 ≤ n ≤ 10^6, 1 ≤ q ≤ 10^6) — the size of the permutation p and the number of queries.
The second line contains n pairwise distinct integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, p_i ≠ p_j for i ≠ j) — permutation p.
The third line contains q integers l_1, l_2, ..., l_q — the first parts of the queries.
The fourth line contains q integers r_1, r_2, ..., r_q — the second parts of the queries.
It's guaranteed that 1 ≤ l_i ≤ r_i ≤ n for all queries.
Output
Print q integers — the values f(l_i, r_i) for the corresponding queries.
Example
Input
4 5 3 1 4 2 2 1 1 2 1 2 3 4 4 1
Output
1 6 8 5 1
Note
Description of the queries:
- f(2, 2) = (2 - 2 + 1) + f(2, 1) + f(3, 2) = 1 + 0 + 0 = 1;
- f(1, 3) = (3 - 1 + 1) + f(1, 2) + f(4, 3) = 3 + (2 - 1 + 1) + f(1, 0) + f(2, 2) = 3 + 2 + (2 - 2 + 1) = 6;
- f(1, 4) = (4 - 1 + 1) + f(1, 2) + f(4, 4) = 4 + 3 + 1 = 8;
- f(2, 4) = (4 - 2 + 1) + f(2, 2) + f(4, 4) = 3 + 1 + 1 = 5;
- f(1, 1) = (1 - 1 + 1) + 0 + 0 = 1.
inputFormat
Input
The first line contains two integers n and q (1 ≤ n ≤ 10^6, 1 ≤ q ≤ 10^6) — the size of the permutation p and the number of queries.
The second line contains n pairwise distinct integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, p_i ≠ p_j for i ≠ j) — permutation p.
The third line contains q integers l_1, l_2, ..., l_q — the first parts of the queries.
The fourth line contains q integers r_1, r_2, ..., r_q — the second parts of the queries.
It's guaranteed that 1 ≤ l_i ≤ r_i ≤ n for all queries.
outputFormat
Output
Print q integers — the values f(l_i, r_i) for the corresponding queries.
Example
Input
4 5 3 1 4 2 2 1 1 2 1 2 3 4 4 1
Output
1 6 8 5 1
Note
Description of the queries:
- f(2, 2) = (2 - 2 + 1) + f(2, 1) + f(3, 2) = 1 + 0 + 0 = 1;
- f(1, 3) = (3 - 1 + 1) + f(1, 2) + f(4, 3) = 3 + (2 - 1 + 1) + f(1, 0) + f(2, 2) = 3 + 2 + (2 - 2 + 1) = 6;
- f(1, 4) = (4 - 1 + 1) + f(1, 2) + f(4, 4) = 4 + 3 + 1 = 8;
- f(2, 4) = (4 - 2 + 1) + f(2, 2) + f(4, 4) = 3 + 1 + 1 = 5;
- f(1, 1) = (1 - 1 + 1) + 0 + 0 = 1.
样例
4 5
3 1 4 2
2 1 1 2 1
2 3 4 4 1
1 6 8 5 1
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