#D2813. Reversing Encryption

    ID: 2343 Type: Default 1000ms 256MiB

Reversing Encryption

Reversing Encryption

A string s of length n can be encrypted by the following algorithm:

  • iterate over all divisors of n in decreasing order (i.e. from n to 1),
  • for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at position 1 and ends at position d).

For example, the above algorithm applied to the string s="codeforces" leads to the following changes: "codeforces" → "secrofedoc" → "orcesfedoc" → "rocesfedoc" → "rocesfedoc" (obviously, the last reverse operation doesn't change the string because d=1).

You are given the encrypted string t. Your task is to decrypt this string, i.e., to find a string s such that the above algorithm results in string t. It can be proven that this string s always exists and is unique.

Input

The first line of input consists of a single integer n (1 ≤ n ≤ 100) — the length of the string t. The second line of input consists of the string t. The length of t is n, and it consists only of lowercase Latin letters.

Output

Print a string s such that the above algorithm results in t.

Examples

Input

10 rocesfedoc

Output

codeforces

Input

16 plmaetwoxesisiht

Output

thisisexampletwo

Input

1 z

Output

z

Note

The first example is described in the problem statement.

inputFormat

Input

The first line of input consists of a single integer n (1 ≤ n ≤ 100) — the length of the string t. The second line of input consists of the string t. The length of t is n, and it consists only of lowercase Latin letters.

outputFormat

Output

Print a string s such that the above algorithm results in t.

Examples

Input

10 rocesfedoc

Output

codeforces

Input

16 plmaetwoxesisiht

Output

thisisexampletwo

Input

1 z

Output

z

Note

The first example is described in the problem statement.

样例

10
rocesfedoc
codeforces

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