#D2813. Reversing Encryption
Reversing Encryption
Reversing Encryption
A string s of length n can be encrypted by the following algorithm:
- iterate over all divisors of n in decreasing order (i.e. from n to 1),
- for each divisor d, reverse the substring s[1 ... d] (i.e. the substring which starts at position 1 and ends at position d).
For example, the above algorithm applied to the string s="codeforces" leads to the following changes: "codeforces" → "secrofedoc" → "orcesfedoc" → "rocesfedoc" → "rocesfedoc" (obviously, the last reverse operation doesn't change the string because d=1).
You are given the encrypted string t. Your task is to decrypt this string, i.e., to find a string s such that the above algorithm results in string t. It can be proven that this string s always exists and is unique.
Input
The first line of input consists of a single integer n (1 ≤ n ≤ 100) — the length of the string t. The second line of input consists of the string t. The length of t is n, and it consists only of lowercase Latin letters.
Output
Print a string s such that the above algorithm results in t.
Examples
Input
10 rocesfedoc
Output
codeforces
Input
16 plmaetwoxesisiht
Output
thisisexampletwo
Input
1 z
Output
z
Note
The first example is described in the problem statement.
inputFormat
Input
The first line of input consists of a single integer n (1 ≤ n ≤ 100) — the length of the string t. The second line of input consists of the string t. The length of t is n, and it consists only of lowercase Latin letters.
outputFormat
Output
Print a string s such that the above algorithm results in t.
Examples
Input
10 rocesfedoc
Output
codeforces
Input
16 plmaetwoxesisiht
Output
thisisexampletwo
Input
1 z
Output
z
Note
The first example is described in the problem statement.
样例
10
rocesfedoc
codeforces
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