#B2616. Chasing Run
Chasing Run
Chasing Run
In this problem, two runners start at the same time. Runner A has a speed of 5 m/s, and Runner B has a speed of 8 m/s. Runner B starts 100 m behind Runner A. Your task is to determine the time (in seconds) it takes for Runner B to catch up with Runner A.
Using the formula below, you can calculate the required time:
$$ t = \frac{100}{8-5} = \frac{100}{3} \text{ seconds} $$
Output a single number representing the answer. In C++ solutions, please use cout
to output the result.
inputFormat
This problem does not require any input.
outputFormat
Output a single number that represents the time (in seconds) after which Runner B catches up with Runner A. The answer should be printed with a precision of at least 6 decimal places.
sample
33.333333